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3/4x-2+2/5x=90
We move all terms to the left:
3/4x-2+2/5x-(90)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3/4x+2/5x-92=0
We calculate fractions
15x/20x^2+8x/20x^2-92=0
We multiply all the terms by the denominator
15x+8x-92*20x^2=0
We add all the numbers together, and all the variables
23x-92*20x^2=0
Wy multiply elements
-1840x^2+23x=0
a = -1840; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-1840)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-1840}=\frac{-46}{-3680} =1/80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-1840}=\frac{0}{-3680} =0 $
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