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3/4x-5=1x
We move all terms to the left:
3/4x-5-(1x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-1x+3/4x-5=0
We multiply all the terms by the denominator
-1x*4x-5*4x+3=0
Wy multiply elements
-4x^2-20x+3=0
a = -4; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·(-4)·3
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-8\sqrt{7}}{2*-4}=\frac{20-8\sqrt{7}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+8\sqrt{7}}{2*-4}=\frac{20+8\sqrt{7}}{-8} $
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