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3/4x-5=2x
We move all terms to the left:
3/4x-5-(2x)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
-2x+3/4x-5=0
We multiply all the terms by the denominator
-2x*4x-5*4x+3=0
Wy multiply elements
-8x^2-20x+3=0
a = -8; b = -20; c = +3;
Δ = b2-4ac
Δ = -202-4·(-8)·3
Δ = 496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{496}=\sqrt{16*31}=\sqrt{16}*\sqrt{31}=4\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{31}}{2*-8}=\frac{20-4\sqrt{31}}{-16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{31}}{2*-8}=\frac{20+4\sqrt{31}}{-16} $
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