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3/4x=2x-
We move all terms to the left:
3/4x-(2x-)=0
Domain of the equation: 4x!=0We add all the numbers together, and all the variables
x!=0/4
x!=0
x∈R
3/4x-(+2x)=0
We get rid of parentheses
3/4x-2x=0
We multiply all the terms by the denominator
-2x*4x+3=0
Wy multiply elements
-8x^2+3=0
a = -8; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-8)·3
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*-8}=\frac{0-4\sqrt{6}}{-16} =-\frac{4\sqrt{6}}{-16} =-\frac{\sqrt{6}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*-8}=\frac{0+4\sqrt{6}}{-16} =\frac{4\sqrt{6}}{-16} =\frac{\sqrt{6}}{-4} $
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