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3/4x=4x-5
We move all terms to the left:
3/4x-(4x-5)=0
Domain of the equation: 4x!=0We get rid of parentheses
x!=0/4
x!=0
x∈R
3/4x-4x+5=0
We multiply all the terms by the denominator
-4x*4x+5*4x+3=0
Wy multiply elements
-16x^2+20x+3=0
a = -16; b = 20; c = +3;
Δ = b2-4ac
Δ = 202-4·(-16)·3
Δ = 592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{592}=\sqrt{16*37}=\sqrt{16}*\sqrt{37}=4\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-4\sqrt{37}}{2*-16}=\frac{-20-4\sqrt{37}}{-32} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+4\sqrt{37}}{2*-16}=\frac{-20+4\sqrt{37}}{-32} $
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