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3/4x=5-3/2x
We move all terms to the left:
3/4x-(5-3/2x)=0
Domain of the equation: 4x!=0
x!=0/4
x!=0
x∈R
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
3/4x-(-3/2x+5)=0
We get rid of parentheses
3/4x+3/2x-5=0
We calculate fractions
6x/8x^2+12x/8x^2-5=0
We multiply all the terms by the denominator
6x+12x-5*8x^2=0
We add all the numbers together, and all the variables
18x-5*8x^2=0
Wy multiply elements
-40x^2+18x=0
a = -40; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-40)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-40}=\frac{-36}{-80} =9/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-40}=\frac{0}{-80} =0 $
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