3/4x=9*x=12

Solution for 3/4x=9*x=12 equation:

3/4x=9x=12

We move all terms to the left:

3/4x-(9x)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We add all the numbers together, and all the variables

-9x+3/4x=0

We multiply all the terms by the denominator


-9x*4x+3=0

Wy multiply elements

-36x^2+3=0

a = -36; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-36)·3
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*-36}=\frac{0-12\sqrt{3}}{-72}
=-\frac{12\sqrt{3}}{-72}
=-\frac{\sqrt{3}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*-36}=\frac{0+12\sqrt{3}}{-72}
=\frac{12\sqrt{3}}{-72}
=\frac{\sqrt{3}}{-6}
$