3/4x=x-12

Solution for 3/4x=x-12 equation:

3/4x=x-12

We move all terms to the left:

3/4x-(x-12)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R


We get rid of parentheses

3/4x-x+12=0

We multiply all the terms by the denominator


-x*4x+12*4x+3=0

Wy multiply elements

-4x^2+48x+3=0

a = -4; b = 48; c = +3;
Δ = b2-4ac
Δ = 482-4·(-4)·3
Δ = 2352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2352}=\sqrt{784*3}=\sqrt{784}*\sqrt{3}=28\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-28\sqrt{3}}{2*-4}=\frac{-48-28\sqrt{3}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+28\sqrt{3}}{2*-4}=\frac{-48+28\sqrt{3}}{-8}
$