3/4y+3(1/2y+1)=4y-4

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Solution for 3/4y+3(1/2y+1)=4y-4 equation: 


y in (-oo:+oo)

3*((1/2)*y+1)+(3/4)*y = 4*y-4 // - 4*y-4

3*((1/2)*y+1)+(3/4)*y-(4*y)+4 = 0

3*((1/2)*y+1)+(3/4)*y-4*y+4 = 0

3*(1/2*y+1)+(3*y)/4-4*y+4 = 0

(3*4*(1/2*y+1))/4+(3*y)/4+(-4*4*y)/4+(4^2)/4 = 0

3*4*(1/2*y+1)+3*y-4*4*y+16 = 0

9*y-16*y+12+16 = 0

12-7*y+16 = 0

28-7*y = 0

(28-7*y)/4 = 0

(28-7*y)/4 = 0 // * 4

28-7*y = 0

28-7*y = 0 // - 28

-7*y = -28 // : -7

y = -28/(-7)

y = 4

y = 4

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