3/4y-(y+2/5)=1/40(y-2)

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Solution for 3/4y-(y+2/5)=1/40(y-2) equation: 



3/4y-(y+2/5)=1/40(y-2)

We move all terms to the left:

3/4y-(y+2/5)-(1/40(y-2))=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R





Domain of the equation: 40(y-2))!=0

y∈R



We add all the numbers together, and all the variables

3/4y-(+y+2/5)-(1/40(y-2))=0

We get rid of parentheses

3/4y-y-(1/40(y-2))-2/5=0

We calculate fractions


(600yy/(800y^2y+(-(1*4y*5)/(800y^2y+(-1280y^2)/(800y^2y-y=0

We can not solve this equation

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