3/4y-(y-1/3)=1/12(y-4)

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Solution for 3/4y-(y-1/3)=1/12(y-4) equation: 


y in (-oo:+oo)

(3/4)*y-y+1/3 = (1/12)*(y-4) // - (1/12)*(y-4)

(3/4)*y-((1/12)*(y-4))-y+1/3 = 0

(-1/12)*(y-4)+(3/4)*y-y+1/3 = 0

(3*y)/4-1/12*(y-4)-y+1/3 = 0

(-1/12*3*4*(y-4))/(3*4)+(3*3*y)/(3*4)+(3*4*(-y))/(3*4)+(1*4)/(3*4) = 0

3*3*y-1/12*3*4*(y-4)+3*4*(-y)+1*4 = 0

8*y-12*y+4+4 = 0

4-4*y+4 = 0

8-4*y = 0

(8-4*y)/(3*4) = 0

(8-4*y)/(3*4) = 0 // * 3*4

8-4*y = 0

8-4*y = 0 // - 8

-4*y = -8 // : -4

y = -8/(-4)

y = 2

y = 2

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