3/4y-(y-2/5)=1/40(y-2)

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Solution for 3/4y-(y-2/5)=1/40(y-2) equation: 


y in (-oo:+oo)

(3/4)*y-y+2/5 = (1/40)*(y-2) // - (1/40)*(y-2)

(3/4)*y-((1/40)*(y-2))-y+2/5 = 0

(-1/40)*(y-2)+(3/4)*y-y+2/5 = 0

(3*y)/4-1/40*(y-2)-y+2/5 = 0

(-1/40*4*5*(y-2))/(4*5)+(3*5*y)/(4*5)+(4*5*(-y))/(4*5)+(2*4)/(4*5) = 0

3*5*y-1/40*4*5*(y-2)+4*5*(-y)+2*4 = 0

29/2*y-20*y+1+8 = 0

1-11/2*y+8 = 0

9-11/2*y = 0

(9-11/2*y)/(4*5) = 0

(9-11/2*y)/(4*5) = 0 // * 4*5

9-11/2*y = 0

9-11/2*y = 0 // - 9

-11/2*y = -9 // : -11/2

y = -9/(-11/2)

y = 18/11

y = 18/11

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