3/4y-5=-1+(1/4y

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Solution for 3/4y-5=-1+(1/4y equation:



3/4y-5=-1+(1/4y
We move all terms to the left:
3/4y-5-(-1+(1/4y)=0
Domain of the equation: 4y!=0
y!=0/4
y!=0
y∈R
Domain of the equation: 4y)-5!=0
y!=0/1
y!=0
y∈R
We add all the numbers together, and all the variables
3/4y-(-1+(+1/4y)-5=0
We calculate fractions
12y/16y^2+(-(-1+(+1*4y)/16y^2=0
We multiply all the terms by the denominator
12y+(-(-1+(+1*4y)=0
We calculate terms in parentheses: +(-(-1+(+1*4y), so:
-(-1+(+1*4y
We calculate terms in parentheses: +(-(-1+(+1*4y), so:
-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
We calculate terms in parentheses: +(-(-1+(+1*4y), so:
-(-1+(+1*4y
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-(-1+(+1*4y
We calculate terms in parentheses: +(-(-1+(+1*4y), so:
-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
We calculate terms in parentheses: +(-(-1+(+1*4y), so:
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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-(-1+(+1*4y
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