3/4y=2y+201/2

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Solution for 3/4y=2y+201/2 equation: 



3/4y=2y+201/2

We move all terms to the left:

3/4y-(2y+201/2)=0



Domain of the equation: 4y!=0

y!=0/4

y!=0

y∈R



We add all the numbers together, and all the variables

3/4y-(+2y+201/2)=0

We get rid of parentheses

3/4y-2y-201/2=0

We calculate fractions

There is no solution for this equation

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