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3/4y=y
We move all terms to the left:
3/4y-(y)=0
Domain of the equation: 4y!=0We add all the numbers together, and all the variables
y!=0/4
y!=0
y∈R
-1y+3/4y=0
We multiply all the terms by the denominator
-1y*4y+3=0
Wy multiply elements
-4y^2+3=0
a = -4; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·(-4)·3
Δ = 48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48}=\sqrt{16*3}=\sqrt{16}*\sqrt{3}=4\sqrt{3}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{3}}{2*-4}=\frac{0-4\sqrt{3}}{-8} =-\frac{4\sqrt{3}}{-8} =-\frac{\sqrt{3}}{-2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{3}}{2*-4}=\frac{0+4\sqrt{3}}{-8} =\frac{4\sqrt{3}}{-8} =\frac{\sqrt{3}}{-2} $
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