3/4z+4=12

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Solution for 3/4z+4=12 equation: 



3/4z+4=12

We move all terms to the left:

3/4z+4-(12)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

3/4z-8=0

We multiply all the terms by the denominator


-8*4z+3=0

Wy multiply elements

-32z+3=0

We move all terms containing z to the left, all other terms to the right

-32z=-3

z=-3/-32

z=3/32

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