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3/4z-1/4+3=2/4z+5
We move all terms to the left:
3/4z-1/4+3-(2/4z+5)=0
Domain of the equation: 4z!=0
z!=0/4
z!=0
z∈R
Domain of the equation: 4z+5)!=0We get rid of parentheses
z∈R
3/4z-2/4z-5+3-1/4=0
We calculate fractions
-5+3=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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