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3/5(1+n)=-1/2n
We move all terms to the left:
3/5(1+n)-(-1/2n)=0
Domain of the equation: 5(1+n)!=0
n∈R
Domain of the equation: 2n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
3/5(n+1)-(-1/2n)=0
We get rid of parentheses
3/5(n+1)+1/2n=0
We calculate fractions
6n/(10n^2+10n)+(5nn/(10n^2+10n)=0
We calculate terms in parentheses: +(5nn/(10n^2+10n), so:We multiply all the terms by the denominator
5nn/(10n^2+10n
We multiply all the terms by the denominator
5nn
Back to the equation:
+(5nn)
6n+5nn*(10n^2+10n)=0
We multiply parentheses
50n^3+50n^2+6n=0
We do not support enpression: n^3
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