3/5(10+15y)+7=-2/3(12-24y)

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Solution for 3/5(10+15y)+7=-2/3(12-24y) equation:



3/5(10+15y)+7=-2/3(12-24y)
We move all terms to the left:
3/5(10+15y)+7-(-2/3(12-24y))=0
Domain of the equation: 5(10+15y)!=0
y∈R
Domain of the equation: 3(12-24y))!=0
y∈R
We add all the numbers together, and all the variables
3/5(15y+10)-(-2/3(-24y+12))+7=0
We calculate fractions
(9y(-)/(5(15y+10)*3(-24y+12)))+(-(-10y1)/(5(15y+10)*3(-24y+12)))+7=0
We calculate terms in parentheses: +(9y(-)/(5(15y+10)*3(-24y+12))), so:
9y(-)/(5(15y+10)*3(-24y+12))
We add all the numbers together, and all the variables
9y0/(5(15y+10)*3(-24y+12))
We multiply all the terms by the denominator
9y0
We add all the numbers together, and all the variables
9y
Back to the equation:
+(9y)
We calculate terms in parentheses: +(-(-10y1)/(5(15y+10)*3(-24y+12))), so:
-(-10y1)/(5(15y+10)*3(-24y+12))
We add all the numbers together, and all the variables
-(-10y)/(5(15y+10)*3(-24y+12))
We multiply all the terms by the denominator
-(-10y)
We get rid of parentheses
10y
Back to the equation:
+(10y)
We add all the numbers together, and all the variables
19y+7=0
We move all terms containing y to the left, all other terms to the right
19y=-7
y=-7/19
y=-7/19

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