3/5(10x+25)-12=-1/3(18x-27)

Solution for 3/5(10x+25)-12=-1/3(18x-27) equation:

3/5(10x+25)-12=-1/3(18x-27)

We move all terms to the left:

3/5(10x+25)-12-(-1/3(18x-27))=0


Domain of the equation: 5(10x+25)!=0

x∈R



Domain of the equation: 3(18x-27))!=0

x∈R


We calculate fractions


(9x1/(5(10x+25)*3(18x-27)))+(-(-5x1)/(5(10x+25)*3(18x-27)))-12=0


We calculate terms in parentheses: +(9x1/(5(10x+25)*3(18x-27))), so:

9x1/(5(10x+25)*3(18x-27))

We multiply all the terms by the denominator


9x1

We add all the numbers together, and all the variables

9x

Back to the equation:

+(9x)



We calculate terms in parentheses: +(-(-5x1)/(5(10x+25)*3(18x-27))), so:

-(-5x1)/(5(10x+25)*3(18x-27))

We add all the numbers together, and all the variables

-(-5x)/(5(10x+25)*3(18x-27))

We multiply all the terms by the denominator


-(-5x)

We get rid of parentheses

5x

Back to the equation:

+(5x)


We add all the numbers together, and all the variables

14x-12=0

We move all terms containing x to the left, all other terms to the right

14x=12

x=12/14

x=6/7