3/5(10x+5)=27

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Solution for 3/5(10x+5)=27 equation: 



3/5(10x+5)=27

We move all terms to the left:

3/5(10x+5)-(27)=0



Domain of the equation: 5(10x+5)!=0

x∈R



We multiply all the terms by the denominator


-27*5(10x+5)+3=0

Wy multiply elements

-135x(1+3=0

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