3/5(20c+5)=12c-9

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Solution for 3/5(20c+5)=12c-9 equation: 



3/5(20c+5)=12c-9

We move all terms to the left:

3/5(20c+5)-(12c-9)=0



Domain of the equation: 5(20c+5)!=0

c∈R



We get rid of parentheses

3/5(20c+5)-12c+9=0

We multiply all the terms by the denominator


-12c*5(20c+5)+9*5(20c+5)+3=0

Wy multiply elements

-60c^2(2+45c(2+3=0

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