3/5(20x-35)=-21+12x

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Solution for 3/5(20x-35)=-21+12x equation: 


x in (-oo:+oo)

(3/5)*(20*x-35) = 12*x-21 // - 12*x-21

(3/5)*(20*x-35)-(12*x)+21 = 0

(3/5)*(20*x-35)-12*x+21 = 0

3/5*(20*x-35)-12*x+21 = 0

3/5*(20*x-35)-12*x+21 = 0

21-21 = 0

0 = 0

0 = 0

x belongs to the empty set

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