3/5(2m-10)=2/3m=10

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Solution for 3/5(2m-10)=2/3m=10 equation: 



3/5(2m-10)=2/3m=10

We move all terms to the left:

3/5(2m-10)-(2/3m)=0



Domain of the equation: 5(2m-10)!=0

m∈R





Domain of the equation: 3m)!=0

m!=0/1

m!=0

m∈R



We add all the numbers together, and all the variables

3/5(2m-10)-(+2/3m)=0

We get rid of parentheses

3/5(2m-10)-2/3m=0

We calculate fractions


9m/(30m^2-150m)+(-10m2/(30m^2-150m)=0



We calculate terms in parentheses: +(-10m2/(30m^2-150m), so:

-10m2/(30m^2-150m

We multiply all the terms by the denominator


-10m2

We add all the numbers together, and all the variables

-10m^2

Back to the equation:

+(-10m^2)



We get rid of parentheses

-10m^2+9m/(30m^2-150m)=0

We multiply all the terms by the denominator


-10m^2*(30m^2-150m)+9m=0

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