3/5(2m-20)=2/3m+10

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Solution for 3/5(2m-20)=2/3m+10 equation: 


m in (-oo:+oo)

(3/5)*(2*m-20) = (2/3)*m+10 // - (2/3)*m+10

(3/5)*(2*m-20)-((2/3)*m)-10 = 0

(3/5)*(2*m-20)+(-2/3)*m-10 = 0

3/5*(2*m-20)+(-2*m)/3-10 = 0

(3/5*3*(2*m-20))/3+(-2*m)/3+(-10*3)/3 = 0

3/5*3*(2*m-20)-2*m-10*3 = 0

8/5*m-36-30 = 0

8/5*m-66 = 0

(8/5*m-66)/3 = 0

(8/5*m-66)/3 = 0 // * 3

8/5*m-66 = 0

8/5*m-66 = 0 // + 66

8/5*m = 66 // : 8/5

m = 66/8/5

m = 165/4

m = 165/4

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