3/5(2x+5)=2/5(2x+7)

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Solution for 3/5(2x+5)=2/5(2x+7) equation: 



3/5(2x+5)=2/5(2x+7)

We move all terms to the left:

3/5(2x+5)-(2/5(2x+7))=0



Domain of the equation: 5(2x+5)!=0

x∈R





Domain of the equation: 5(2x+7))!=0

x∈R



We calculate fractions


(15x2/(5(2x+5)*5(2x+7)))+(-10x2/(5(2x+5)*5(2x+7)))=0



We calculate terms in parentheses: +(15x2/(5(2x+5)*5(2x+7))), so:

15x2/(5(2x+5)*5(2x+7))

We multiply all the terms by the denominator


15x2

We add all the numbers together, and all the variables

15x^2

Back to the equation:

+(15x^2)





We calculate terms in parentheses: +(-10x2/(5(2x+5)*5(2x+7))), so:

-10x2/(5(2x+5)*5(2x+7))

We multiply all the terms by the denominator


-10x2

We add all the numbers together, and all the variables

-10x^2

Back to the equation:

+(-10x^2)



We add all the numbers together, and all the variables

15x^2+(-10x^2)=0

We get rid of parentheses

15x^2-10x^2=0

We add all the numbers together, and all the variables

5x^2=0

a = 5; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{10}=0$

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