3/5(2x-1)=1/3(x+3)

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Solution for 3/5(2x-1)=1/3(x+3) equation: 



3/5(2x-1)=1/3(x+3)

We move all terms to the left:

3/5(2x-1)-(1/3(x+3))=0



Domain of the equation: 5(2x-1)!=0

x∈R





Domain of the equation: 3(x+3))!=0

x∈R



We calculate fractions


(9xx/(5(2x-1)*3(x+3)))+(-5x2/(5(2x-1)*3(x+3)))=0



We calculate terms in parentheses: +(9xx/(5(2x-1)*3(x+3))), so:

9xx/(5(2x-1)*3(x+3))

We multiply all the terms by the denominator


9xx

Back to the equation:

+(9xx)





We calculate terms in parentheses: +(-5x2/(5(2x-1)*3(x+3))), so:

-5x2/(5(2x-1)*3(x+3))

We multiply all the terms by the denominator


-5x2

We add all the numbers together, and all the variables

-5x^2

Back to the equation:

+(-5x^2)



We get rid of parentheses

-5x^2+9xx=0

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