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3/5(35x+15)=2/3(9x-21)
We move all terms to the left:
3/5(35x+15)-(2/3(9x-21))=0
Domain of the equation: 5(35x+15)!=0
x∈R
Domain of the equation: 3(9x-21))!=0We calculate fractions
x∈R
(9x9/(5(35x+15)*3(9x-21)))+(-10x3/(5(35x+15)*3(9x-21)))=0
We calculate terms in parentheses: +(9x9/(5(35x+15)*3(9x-21))), so:
9x9/(5(35x+15)*3(9x-21))
We multiply all the terms by the denominator
9x9
We add all the numbers together, and all the variables
9x^9
We do not support expression: x^9
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