3/5(3a-10)=-1/5(2a-9)

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Solution for 3/5(3a-10)=-1/5(2a-9) equation: 



3/5(3a-10)=-1/5(2a-9)

We move all terms to the left:

3/5(3a-10)-(-1/5(2a-9))=0



Domain of the equation: 5(3a-10)!=0

a∈R





Domain of the equation: 5(2a-9))!=0

a∈R



We calculate fractions


(15a2/(5(3a-10)*5(2a-9)))+(-(-5a3)/(5(3a-10)*5(2a-9)))=0



We calculate terms in parentheses: +(15a2/(5(3a-10)*5(2a-9))), so:

15a2/(5(3a-10)*5(2a-9))

We multiply all the terms by the denominator


15a2

We add all the numbers together, and all the variables

15a^2

Back to the equation:

+(15a^2)





We calculate terms in parentheses: +(-(-5a3)/(5(3a-10)*5(2a-9))), so:

-(-5a3)/(5(3a-10)*5(2a-9))

We add all the numbers together, and all the variables

-(-5a^3)/(5(3a-10)*5(2a-9))

We multiply all the terms by the denominator


-(-5a^3)

We do not support eapression: a^3

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