3/5(3x-2)+1/10(4x-5)=25

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Solution for 3/5(3x-2)+1/10(4x-5)=25 equation: 



3/5(3x-2)+1/10(4x-5)=25

We move all terms to the left:

3/5(3x-2)+1/10(4x-5)-(25)=0



Domain of the equation: 5(3x-2)!=0

x∈R





Domain of the equation: 10(4x-5)!=0

x∈R



We calculate fractions


(30x4/(5(3x-2)*10(4x-5))+(5x3/(5(3x-2)*10(4x-5))-25=0

We can not solve this equation

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