3/5(4+2/3B)+b=15

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Solution for 3/5(4+2/3B)+b=15 equation: 


x in (-oo:+oo)

(3/5)*((2/3)*B+4)+b = 15 // - 15

(3/5)*((2/3)*B+4)+b-15 = 0

3/5*(2/3*B+4)+b-15 = 0

3/5*(2/3*B+4)+b-15 = 0

2/5*B+b-15+12/5 = 0

2/5*B+b-63/5 = 0

2/5*B+b-63/5 = 0

x belongs to the empty set

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