3/5(50-25x)=6(2-3x)

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Solution for 3/5(50-25x)=6(2-3x) equation: 



3/5(50-25x)=6(2-3x)

We move all terms to the left:

3/5(50-25x)-(6(2-3x))=0



Domain of the equation: 5(50-25x)!=0

x∈R



We add all the numbers together, and all the variables

3/5(-25x+50)-(6(-3x+2))=0

We multiply all the terms by the denominator


-((6(-3x+2)))*5(-25x+50)+3=0



We calculate terms in parentheses: -((6(-3x+2)))*5(-25x+50), so:

(6(-3x+2)))*5(-25x+50

We add all the numbers together, and all the variables

-25x+(6(-3x+2)))*5(+50

Back to the equation:

-(-25x+(6(-3x+2)))*5(+50)



We add all the numbers together, and all the variables

-(-25x+(6(-3x+2)))*550+3=0

We move all terms containing x to the left, all other terms to the right

-(-25x+(6(-3x+2)))*550=-3

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