3/5(5j+10)=1/3(3j-6)

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Solution for 3/5(5j+10)=1/3(3j-6) equation:



3/5(5j+10)=1/3(3j-6)
We move all terms to the left:
3/5(5j+10)-(1/3(3j-6))=0
Domain of the equation: 5(5j+10)!=0
j∈R
Domain of the equation: 3(3j-6))!=0
j∈R
We calculate fractions
(9j3/(5(5j+10)*3(3j-6)))+(-5j5/(5(5j+10)*3(3j-6)))=0
We calculate terms in parentheses: +(9j3/(5(5j+10)*3(3j-6))), so:
9j3/(5(5j+10)*3(3j-6))
We multiply all the terms by the denominator
9j3
We add all the numbers together, and all the variables
9j^3
We do not support ejpression: j^3

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