3/5(5u+10)=27

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Solution for 3/5(5u+10)=27 equation: 



3/5(5u+10)=27

We move all terms to the left:

3/5(5u+10)-(27)=0



Domain of the equation: 5(5u+10)!=0

u∈R



We multiply all the terms by the denominator


-27*5(5u+10)+3=0

Wy multiply elements

-135u(5+3=0

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