3/5(9x-18)=7/6(8-7x)

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Solution for 3/5(9x-18)=7/6(8-7x) equation: 



3/5(9x-18)=7/6(8-7x)

We move all terms to the left:

3/5(9x-18)-(7/6(8-7x))=0



Domain of the equation: 5(9x-18)!=0

x∈R





Domain of the equation: 6(8-7x))!=0

x∈R



We add all the numbers together, and all the variables

3/5(9x-18)-(7/6(-7x+8))=0

We calculate fractions


(18x(-)/(5(9x-18)*6(-7x+8)))+(-35x9/(5(9x-18)*6(-7x+8)))=0



We calculate terms in parentheses: +(18x(-)/(5(9x-18)*6(-7x+8))), so:

18x(-)/(5(9x-18)*6(-7x+8))

We add all the numbers together, and all the variables

18x0/(5(9x-18)*6(-7x+8))

We multiply all the terms by the denominator


18x0

We add all the numbers together, and all the variables

18x

Back to the equation:

+(18x)





We calculate terms in parentheses: +(-35x9/(5(9x-18)*6(-7x+8))), so:

-35x9/(5(9x-18)*6(-7x+8))

We multiply all the terms by the denominator


-35x9

We add all the numbers together, and all the variables

-35x^9

We do not support expression: x^9

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