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3/5(c+2)=2c-3+2/5c
We move all terms to the left:
3/5(c+2)-(2c-3+2/5c)=0
Domain of the equation: 5(c+2)!=0
c∈R
Domain of the equation: 5c)!=0We add all the numbers together, and all the variables
c!=0/1
c!=0
c∈R
3/5(c+2)-(2c+2/5c-3)=0
We get rid of parentheses
3/5(c+2)-2c-2/5c+3=0
We calculate fractions
-2c+15c/(25c^2+50c)+(-10cc/(25c^2+50c)+3=0
We calculate fractions
We do not support ecpression: c^3
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