3/5(n+12)=21

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Solution for 3/5(n+12)=21 equation: 



3/5(n+12)=21

We move all terms to the left:

3/5(n+12)-(21)=0



Domain of the equation: 5(n+12)!=0

n∈R



We multiply all the terms by the denominator


-21*5(n+12)+3=0

Wy multiply elements

-105n(n+3=0

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