3/5(v-7)=7/10(v+2)

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Solution for 3/5(v-7)=7/10(v+2) equation: 



3/5(v-7)=7/10(v+2)

We move all terms to the left:

3/5(v-7)-(7/10(v+2))=0



Domain of the equation: 5(v-7)!=0

v∈R





Domain of the equation: 10(v+2))!=0

v∈R



We calculate fractions


(30vv/(5(v-7)*10(v+2)))+(-35vv/(5(v-7)*10(v+2)))=0



We calculate terms in parentheses: +(30vv/(5(v-7)*10(v+2))), so:

30vv/(5(v-7)*10(v+2))

We multiply all the terms by the denominator


30vv

Back to the equation:

+(30vv)





We calculate terms in parentheses: +(-35vv/(5(v-7)*10(v+2))), so:

-35vv/(5(v-7)*10(v+2))

We multiply all the terms by the denominator


-35vv

Back to the equation:

+(-35vv)



We get rid of parentheses

30vv-35vv=0

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