3/5(x-12)=-4(x+9)-1

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Solution for 3/5(x-12)=-4(x+9)-1 equation:



3/5(x-12)=-4(x+9)-1
We move all terms to the left:
3/5(x-12)-(-4(x+9)-1)=0
Domain of the equation: 5(x-12)!=0
x∈R
We multiply all the terms by the denominator
-((-4(x+9)-1))*5(x-12)+3=0
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
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(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We calculate terms in parentheses: -((-4(x+9)-1))*5(x-12), so:
(-4(x+9)-1))*5(x-12
We move all terms containing x to the left, all other terms to the right
-((-4(x+9)-1))*5(x-12)=-3

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