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3/5(x-4)-1/3(2x-9)=1/4(x+1)-2
We move all terms to the left:
3/5(x-4)-1/3(2x-9)-(1/4(x+1)-2)=0
Domain of the equation: 5(x-4)!=0
x∈R
Domain of the equation: 3(2x-9)!=0
x∈R
Domain of the equation: 4(x+1)-2)!=0We calculate fractions
x∈R
(36x^22/(5(x-4)*3(2x-9)*4(x+1))+(-20x^2x/(5(x-4)*3(2x-9)*4(x+1))+(-15x^2x/(5(x-4)*3(2x-9)*4(x+1))=0
We calculate terms in parentheses: +(36x^22/(5(x-4)*3(2x-9)*4(x+1))+(-20x^2x/(5(x-4)*3(2x-9)*4(x+1))+(-15x^2x/(5(x-4)*3(2x-9)*4(x+1)), so:
36x^22/(5(x-4)*3(2x-9)*4(x+1))+(-20x^2x/(5(x-4)*3(2x-9)*4(x+1))+(-15x^2x/(5(x-4)*3(2x-9)*4(x+1)
We do not support expression: x^22
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