If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(1*((2*(3/5))/3))/4 = 0
(1*((3/5*2)/3))/4 = 0
(1*(6/5/3))/4 = 0
(2/5*1)/4 = 0
2/5/4 = 0
1/10 = 0
L <> R
| 3x^3y^4/6x^2y^5 | | d+.2=.75 | | y=mx^2+mx-2x^2+3m-x-2 | | y-5/3=4/5 | | y-4.9=11.3 | | -18=w-15 | | -3b+ac=c+4 | | -3+2y=30 | | x=1.166666667+-0.8333333333y | | 3y-8+y+22=7+8y+13-6y | | 4(x-5)=3x+17 | | 4x+6=354 | | 35+.10x=20+.25x | | (8x+5)(4x+7)=0 | | 2x+3=5x+11 | | 60t+40(60-t)=2840 | | 13/19x=65 | | 35+.10x=20.25x | | 8m+3=-53 | | (21)+x+7=8x+14 | | 3/51=5/x | | 12x^4yz^2/20x^7y^5z^2 | | 35=-7-6x | | -10x+-6=44 | | 21+x+7=8x+4 | | -8=1+9x | | 5x+30=4x+15 | | 180=3x+40 | | 14y+18=74 | | 7x+20=3x+4 | | 7x+3+3x+7=40 | | 5(1/2x-1) |