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3/5+7/6x=1/8x
We move all terms to the left:
3/5+7/6x-(1/8x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 8x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7/6x-(+1/8x)+3/5=0
We get rid of parentheses
7/6x-1/8x+3/5=0
We calculate fractions
1152x^2/1200x^2+1400x/1200x^2+(-150x)/1200x^2=0
We multiply all the terms by the denominator
1152x^2+1400x+(-150x)=0
We get rid of parentheses
1152x^2+1400x-150x=0
We add all the numbers together, and all the variables
1152x^2+1250x=0
a = 1152; b = 1250; c = 0;
Δ = b2-4ac
Δ = 12502-4·1152·0
Δ = 1562500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1562500}=1250$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1250)-1250}{2*1152}=\frac{-2500}{2304} =-1+49/576 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1250)+1250}{2*1152}=\frac{0}{2304} =0 $
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