3/5-2/x=2/5x

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Solution for 3/5-2/x=2/5x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3/5-(2/x) = (2/5)*x // - (2/5)*x

3/5-((2/5)*x)-(2/x) = 0

(-2/5)*x-2*x^-1+3/5 = 0

3/5*x^0-2/5*x^1-2*x^-1 = 0

(3/5*x^1-2/5*x^2-2*x^0)/(x^1) = 0 // * x^2

x^1*(3/5*x^1-2/5*x^2-2*x^0) = 0

x^1

(-2/5)*x^2+(3/5)*x-2 = 0

(-2/5)*x^2+(3/5)*x-2 = 0

DELTA = (3/5)^2-(-2*4*(-2/5))

DELTA = -71/25

DELTA < 0

x in { } 

x belongs to the empty set

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