3/5b+17=b

Solution for 3/5b+17=b equation:

3/5b+17=b

We move all terms to the left:

3/5b+17-(b)=0


Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R


We add all the numbers together, and all the variables

-1b+3/5b+17=0

We multiply all the terms by the denominator


-1b*5b+17*5b+3=0

Wy multiply elements

-5b^2+85b+3=0

a = -5; b = 85; c = +3;
Δ = b2-4ac
Δ = 852-4·(-5)·3
Δ = 7285
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-\sqrt{7285}}{2*-5}=\frac{-85-\sqrt{7285}}{-10}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+\sqrt{7285}}{2*-5}=\frac{-85+\sqrt{7285}}{-10}
$