3/5b+20=44

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Solution for 3/5b+20=44 equation: 



3/5b+20=44

We move all terms to the left:

3/5b+20-(44)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

3/5b-24=0

We multiply all the terms by the denominator


-24*5b+3=0

Wy multiply elements

-120b+3=0

We move all terms containing b to the left, all other terms to the right

-120b=-3

b=-3/-120

b=1/40

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