3/5b-2+7b=12-2/5b+14

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Solution for 3/5b-2+7b=12-2/5b+14 equation:



3/5b-2+7b=12-2/5b+14
We move all terms to the left:
3/5b-2+7b-(12-2/5b+14)=0
Domain of the equation: 5b!=0
b!=0/5
b!=0
b∈R
Domain of the equation: 5b+14)!=0
b∈R
We add all the numbers together, and all the variables
3/5b+7b-(-2/5b+26)-2=0
We add all the numbers together, and all the variables
7b+3/5b-(-2/5b+26)-2=0
We get rid of parentheses
7b+3/5b+2/5b-26-2=0
We multiply all the terms by the denominator
7b*5b-26*5b-2*5b+3+2=0
We add all the numbers together, and all the variables
7b*5b-26*5b-2*5b+5=0
Wy multiply elements
35b^2-130b-10b+5=0
We add all the numbers together, and all the variables
35b^2-140b+5=0
a = 35; b = -140; c = +5;
Δ = b2-4ac
Δ = -1402-4·35·5
Δ = 18900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{18900}=\sqrt{900*21}=\sqrt{900}*\sqrt{21}=30\sqrt{21}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-140)-30\sqrt{21}}{2*35}=\frac{140-30\sqrt{21}}{70} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-140)+30\sqrt{21}}{2*35}=\frac{140+30\sqrt{21}}{70} $

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