3/5b-7=2

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Solution for 3/5b-7=2 equation: 



3/5b-7=2

We move all terms to the left:

3/5b-7-(2)=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



We add all the numbers together, and all the variables

3/5b-9=0

We multiply all the terms by the denominator


-9*5b+3=0

Wy multiply elements

-45b+3=0

We move all terms containing b to the left, all other terms to the right

-45b=-3

b=-3/-45

b=1/15

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