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3/5b=2
We move all terms to the left:
3/5b-(2)=0
Domain of the equation: 5b!=0We multiply all the terms by the denominator
b!=0/5
b!=0
b∈R
-2*5b+3=0
Wy multiply elements
-10b+3=0
We move all terms containing b to the left, all other terms to the right
-10b=-3
b=-3/-10
b=3/10
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