3/5c+11=15

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Solution for 3/5c+11=15 equation: 



3/5c+11=15

We move all terms to the left:

3/5c+11-(15)=0



Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



We add all the numbers together, and all the variables

3/5c-4=0

We multiply all the terms by the denominator


-4*5c+3=0

Wy multiply elements

-20c+3=0

We move all terms containing c to the left, all other terms to the right

-20c=-3

c=-3/-20

c=3/20

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