3/5c+3/10c-6=4

Solution for 3/5c+3/10c-6=4 equation:

3/5c+3/10c-6=4

We move all terms to the left:

3/5c+3/10c-6-(4)=0


Domain of the equation: 5c!=0

c!=0/5

c!=0

c∈R



Domain of the equation: 10c!=0

c!=0/10

c!=0

c∈R


We add all the numbers together, and all the variables

3/5c+3/10c-10=0

We calculate fractions


30c/50c^2+15c/50c^2-10=0

We multiply all the terms by the denominator


30c+15c-10*50c^2=0

We add all the numbers together, and all the variables

45c-10*50c^2=0

Wy multiply elements

-500c^2+45c=0

a = -500; b = 45; c = 0;
Δ = b2-4ac
Δ = 452-4·(-500)·0
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-45}{2*-500}=\frac{-90}{-1000}
=9/100
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+45}{2*-500}=\frac{0}{-1000}
=0
$